(version 8 September 2006)
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| You are visitor number | since 8 September 2006 |
Looking at the products for a single meiosis
The final products from a single meiosis together in an ascus, which is either a tetrad (4 spores) or an octad (8 spores).
linear and unordered
Because of the linear segregation in linear tetrad/octads we can use single markers to map distance from centromere
Key is first- versus second -division segregation
In 1st division segregation, the two different alleles segregate at the 1st meiotic division
In 2nd division segreation, the two different alleles segregate at the 2nd meiotic division

Key is that half of all gametes from 2nd div seg are recombinant
Recombination fraction between marker and centromere
= (1/2)*% (2nd division segregation)
The precent 2nd division segregation reaches a limiting value of 2/3. Why?
Cross AB/ab
three types of spores (no order)
Parental ditypes (PD) AB, AB, ab, ab
Nonparental ditypes (NPD) Ab, Ab, aB, aB
Tetratypes (T) AB, ab, Ab, aB
parental ditypes -- all four gametes are parental
nonparental ditypes -- all four gametes are recombinant
Tetratypes -- two parental, two recombinant
What is recombination frequency?
| Tetrad | t + t + + m + m |
t + t m + + + m |
t + + m t + + m |
t + + + t m + m |
t m t m + + + + |
t m + + t + + m |
| Number | 260 | 76 | 4 | 54 | 1 | 5 |
Note that the parental genome is t + / +m, as this is the most common tetrad.
| Tetrad | t + t + + m + m |
t + t m + + + m |
t + + m t + + m |
t + + + t m + m |
t m t m + + + + |
t m + + t + + m |
| Number | 260 | 76 | 4 | 54 | 1 | 5 |
| Type | PD | T | PD | T | NPD | T |
Hence, the t-m recombination frequency is (1/2) Freq(T) + Freq(NPD) = (1/2)(76+54+5)/400 + 1/400 = 0.17
| Tetrad | t + t + + m + m |
t + t m + + + m |
t + + m t + + m |
t + + + t m + m |
t m t m + + + + |
t m + + t + + m |
| Number | 260 | 76 | 4 | 54 | 1 | 5 |
| Division type for t locus | 1st | 1st | 2nd | 2nd | 1st | 2nd |
Hence, frequency 2nd divsion segregation = (4+54+5)/400 = 0.1575, giving the t-centromere distance as (1/2)*0.1575 = 0.079
| Tetrad | t + t + + m + m |
t + t m + + + m |
t + + m t + + m |
t + + + t m + m |
t m t m + + + + |
t m + + t + + m |
| Number | 260 | 76 | 4 | 54 | 1 | 5 | Division type for m locus | 1st | 2nd | 2nd | 1st | 1st | 2nd |
Hence, frequency 2nd division segregation = (76+4+5)/400 = 0.213, giving the t-centromere distance as (1/2)*0.23 = 0.106

What type of tetrad expected from a double-crossover?
Crossovers can involve 2, 3 or all 4 strands. To illustrate the idea, here are particular 2- and 3-strand double crossovers and the resulting tetrads.

